$\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{e^x(x \sin x)}{e^{2 x}-1} d x=$

Question

Aicharya · Accepted Answer

$\int_{\frac{-\pi}{4}}^{\frac{\pi}{4}} \frac{e^x \cdot x \cdot \sin x}{e^{2 x}-1} \mathrm{~d} x=0\left[\begin{array}{c}a \ \because \int_{-a}^a f(x) \mathrm{d} x=0 \ 	ext { if } f(x) 	ext { is an odd function }\end{array}ight]$

$\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{e^x(x \sin x)}{e^{2 x}-1} d x=$

Solution