$\int \frac{e^{x}}{\sqrt{x}}(1+2 x) d x=$

$\int \frac{e^{x}}{\sqrt{x}}(1+2 x) d x=$
  1. $\frac{1}{\sqrt{x}} e^{x}+c$
  2. $2 \sqrt{x} e^{x}+c$
  3. $\frac{\sqrt{x}}{2} e^{x}+c$
  4. $\sqrt{x} e^{x}+c$

Solution

$\begin{aligned} I &=\int \frac{e^{x}}{\sqrt{x}}(1+2 x) d x \\ &=\int e^{x}\left(\frac{1}{\sqrt{x}}+2 \sqrt{x}\right) d x=\int e^{x}\left(2 \sqrt{x}+\frac{1}{\sqrt{x}}\right) d x=2 \int e^{x}\left(\sqrt{x}+\frac{1}{2 \sqrt{x}}\right) d x \\ &=2 e^{x} \sqrt{x}+c \end{aligned}$

Asked in: MHT CET 2020 (14 Oct Shift 1)

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