$\int \frac{d x}{\cos 2 x-\cos ^{2} x}=$

Question

Aicharya · Accepted Answer

$\begin{aligned} \int \frac{d x}{\cos 2 x-\cos ^{2} x} &=\int \frac{1}{2 \cos ^{2} x-1-\cos ^{2} x} d x=\int \frac{1}{\cos ^{2} x-1} d x \ &=\int \frac{-1}{1-\cos ^{2} x} d x=-\int \frac{d x}{\sin ^{2} x}=\int-\cos e c^{2} x d x=\cot x+c \end{aligned}$

$\int \frac{d x}{\cos 2 x-\cos ^{2} x}=$

Solution