$$ \left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{SO}_4ight] \mathrm{Br} \text { and…

$$ \left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{SO}_4ight] \mathrm{Br} \text { and }\left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{Br}ight] \mathrm{SO}_4 $$ are a pair of isomers.
  1. ionisation
  2. ligand
  3. coordination
  4. hydrate

Solution

$$ \begin{aligned} & {\left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{SO}_4ight] \mathrm{Br} ightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{SO}_4ight]^{+}+\mathrm{Br}^{-}} \\ & {\left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{Br}ight] \mathrm{SO}_4 ightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3ight)_5 \mathrm{Br}ight]^{2+}+\mathrm{SO}_4^{2-}} \end{aligned} $$ the molecular formula of both of the above compounds is same but on ionisation they give different ions in solution, so they are called ionisation isomers.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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