$ f(x)= \begin{cases}(1+3 x)^{\frac{4}{x},} & \text { if } x \neq 0, \\ a, & \text { if } x=0 .\end{cases} $…

$ f(x)= \begin{cases}(1+3 x)^{\frac{4}{x},} & \text { if } x \neq 0, \\ a, & \text { if } x=0 .\end{cases} $ If $f$ is continuous, then $\log a=$
  1. $\frac{1}{3}$
  2. $\frac{3}{4}$
  3. $\frac{4}{3}$
  4. 12

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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