$ f(x)= \begin{cases}(1+3 x)^{\frac{4}{x},} & \text { if } x \neq 0, \\ a, & \text { if } x=0 .\end{cases} $…
- $\frac{1}{3}$
- $\frac{3}{4}$
- $\frac{4}{3}$
- 12
Solution
Asked in: AP EAMCET 2018 (24 Apr Shift 2)
Practice more Continuity and Differentiability questions on Aicharya