$\dfrac{\sqrt{3}}{\sqrt{5}}$ rationalised equals
$\dfrac{\sqrt{3}}{\sqrt{5}}$ rationalised equals
- $\dfrac{\sqrt{15}}{5}$
- $\dfrac{3}{5}$
- $\dfrac{\sqrt{3}}{5}$
- $\dfrac{3\sqrt{5}}{5}$
Solution
$\dfrac{\sqrt{3}}{\sqrt{5}} \cdot \dfrac{\sqrt{5}}{\sqrt{5}} = \dfrac{\sqrt{15}}{5}$.
Asked in: MH-SSC-9
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