$\dfrac{6}{\sqrt{2}}$ rationalised equals

$\dfrac{6}{\sqrt{2}}$ rationalised equals
  1. $3\sqrt{2}$
  2. $6\sqrt{2}$
  3. $3$
  4. $\dfrac{6}{2}$

Solution

$\dfrac{6}{\sqrt{2}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{6\sqrt{2}}{2} = 3\sqrt{2}$.

Asked in: MH-SSC-9

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