$\dfrac{4}{2 - \sqrt{2}}$ rationalised equals

$\dfrac{4}{2 - \sqrt{2}}$ rationalised equals
  1. $4 + 2\sqrt{2}$
  2. $2 + \sqrt{2}$
  3. $2 - \sqrt{2}$
  4. $\dfrac{4}{2}$

Solution

Denom $= 4 - 2 = 2$. Numerator $= 4(2 + \sqrt{2}) = 8 + 4\sqrt{2}$. Divide by 2: $4 + 2\sqrt{2}$.

Asked in: MH-SSC-9

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