$\dfrac{2}{\sqrt{6} - \sqrt{2}}$ rationalised equals

$\dfrac{2}{\sqrt{6} - \sqrt{2}}$ rationalised equals
  1. $\dfrac{\sqrt{6} + \sqrt{2}}{2}$
  2. $\sqrt{6} + \sqrt{2}$
  3. $\dfrac{\sqrt{6} - \sqrt{2}}{2}$
  4. $2$

Solution

Denom $= 6 - 2 = 4$. Numerator $= 2(\sqrt{6} + \sqrt{2})$. Result: $\dfrac{\sqrt{6} + \sqrt{2}}{2}$.

Asked in: MH-SSC-9

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