$\dfrac{2}{\sqrt{3} + 1}$ rationalised equals

$\dfrac{2}{\sqrt{3} + 1}$ rationalised equals
  1. $\sqrt{3} - 1$
  2. $\sqrt{3} + 1$
  3. $\dfrac{\sqrt{3} - 1}{2}$
  4. $\dfrac{1}{\sqrt{3}}$

Solution

Multiply by $\dfrac{\sqrt{3} - 1}{\sqrt{3} - 1}$. Denom $= 3 - 1 = 2$. Numerator $= 2(\sqrt{3} - 1)$. Cancel: $\sqrt{3} - 1$.

Asked in: MH-SSC-9

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