$\dfrac{2}{3} \div \dfrac{4}{9}$ equals

$\dfrac{2}{3} \div \dfrac{4}{9}$ equals
  1. $\dfrac{3}{2}$
  2. $\dfrac{8}{27}$
  3. $\dfrac{2}{3}$
  4. $\dfrac{1}{6}$

Solution

$\dfrac{2}{3} \cdot \dfrac{9}{4} = \dfrac{18}{12} = \dfrac{3}{2}$.

Asked in: IMO

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