$\dfrac{2}{3} = \dfrac{4}{6} = \dfrac{6}{9} = k$. Then $k$ equals

$\dfrac{2}{3} = \dfrac{4}{6} = \dfrac{6}{9} = k$. Then $k$ equals
  1. $\dfrac{2}{3}$
  2. $\dfrac{3}{2}$
  3. $1$
  4. $\dfrac{1}{2}$

Solution

All ratios reduce to $\dfrac{2}{3}$.

Asked in: MH-SSC-9

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