$\dfrac{1}{2 + \sqrt{3}}$ rationalised equals

$\dfrac{1}{2 + \sqrt{3}}$ rationalised equals
  1. $2 - \sqrt{3}$
  2. $2 + \sqrt{3}$
  3. $\dfrac{2 - \sqrt{3}}{7}$
  4. $\dfrac{1}{4 - 3}$

Solution

Multiply by $\dfrac{2 - \sqrt{3}}{2 - \sqrt{3}}$. Denominator $= 4 - 3 = 1$. Result: $2 - \sqrt{3}$.

Asked in: MH-SSC-9

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