$\angle$ alt. int. on transversal between two lines: $\angle 1 = (3x + 10)^{\circ}$, $\angle 2 = (4x -…

$\angle$ alt. int. on transversal between two lines: $\angle 1 = (3x + 10)^{\circ}$, $\angle 2 = (4x - 20)^{\circ}$. For lines to be parallel, $x$ equals
  1. $30$
  2. $10$
  3. $20$
  4. $15$

Solution

Equate: $3x + 10 = 4x - 20 \Rightarrow x = 30$.

Asked in: MH-SSC-9

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