$A$ alone takes $20$ days; $B$ alone takes $30$ days. They start together but $A$ leaves after $5$ days. $B$ alone will finish the remaining work in:

Question

Aicharya · Accepted Answer

Combined rate $= \dfrac{1}{20} + \dfrac{1}{30} = \dfrac{5}{60} = \dfrac{1}{12}$. In $5$ days they do $\dfrac{5}{12}$. Remaining $= \dfrac{7}{12}$. $B$'s time $= \dfrac{7}{12} \div \dfrac{1}{30} = \dfrac{7 	imes 30}{12} = \dfrac{45}{2}$ days.

$A$ alone takes $20$ days; $B$ alone takes $30$ days. They start together but $A$ leaves after $5$ days. $B$…

Solution