$ABCD$ is a quadrilateral. The diagonal $BD = 24$ cm and the offsets to it from $A$ and $C$ are $8$ cm and…
$ABCD$ is a quadrilateral. The diagonal $BD = 24$ cm and the offsets to it from $A$ and $C$ are $8$ cm and $10$ cm respectively. Find its area.
- $216 \text{ cm}^{2}$
- $108 \text{ cm}^{2}$
- $192 \text{ cm}^{2}$
- $432 \text{ cm}^{2}$
Solution
Area $= \dfrac{1}{2}\times 24 \times (8+10) = 12 \times 18 = 216 \text{ cm}^{2}$.
Asked in: IMO
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