$A^{2+}, B^{2+}$ and $C^{-}$form an ionic complex like $A_{x-2}\left[B(C)_xight]_2$. If the complex is $75 \%$ dissociated in a solvent with $i=4$, the coordination number of $B$ is

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Aicharya · Accepted Answer

$\begin{gathered}A_{x-2}\left[B(C)_xight]_2 \longrightarrow(x-2) A^{+2}+\left[B(C)_xight]^{-(x-2)} \ A_{x-2}\left[B(C)_xight] \cdot A^{+2} 	ext { and }\left[B(C)_2ight]^{-(x-2)} \ i=1-\alpha+x \alpha-2 \alpha+2 \alpha \ (x-1) \alpha=3 	ext { or } x-1=\frac{3}{\alpha} \ \alpha=0.75, i=4, x=5\end{gathered}$

$A^{2+}, B^{2+}$ and $C^{-}$form an ionic complex like $A_{x-2}\left[B(C)_xight]_2$. If the complex is $75…

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