$(a - b)^{3}$ expands to
$(a - b)^{3}$ expands to
- $a^{3} - 3a^{2}b + 3ab^{2} - b^{3}$
- $a^{3} - b^{3}$
- $a^{3} - 3ab^{2} + b^{3}$
- $(a-b)(a^{2}+ab+b^{2})$
Solution
Standard binomial cube identity for difference.
Asked in: IMO
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