$(8 \times 10^{6}) \div (2 \times 10^{-3}) = ?$
$(8 \times 10^{6}) \div (2 \times 10^{-3}) = ?$
- $4 \times 10^{3}$
- $4 \times 10^{9}$
- $4 \times 10^{-9}$
- $16 \times 10^{9}$
Solution
$\dfrac{8}{2} \times 10^{6-(-3)} = 4 \times 10^{9}$.
Asked in: IMO
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