$8 \mathrm{~mol}$ of $A B_{3}(g)$ are introduced into a $1.0 \mathrm{dm}^{3}$ vessel. If it dissociates as $2 A B_{3}(g) ightleftharpoons A_{2}(g)+3 B_{2}(g) .$ At equilibrium, 2 mol of $A_{2}$ are found to be present. The equilibrium constant of this reaction is

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Aicharya · Accepted Answer

now $K_{C}=\frac{\left[A_{2}ight]\left[B_{2}ight]^{3}}{\left[A B_{3}ight]^{2}}=\frac{2 / 1 	imes[6 / 1]^{3}}{[4 / 1]^{2}}=27$ *

$8 \mathrm{~mol}$ of $A B_{3}(g)$ are introduced into a $1.0 \mathrm{dm}^{3}$ vessel. If it dissociates as…

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