$(8, 15, ?)$ is a Pythagorean triple. The third member is

$(8, 15, ?)$ is a Pythagorean triple. The third member is
  1. $17$
  2. $16$
  3. $18$
  4. $23$

Solution

$8^{2} + 15^{2} = 64 + 225 = 289 = 17^{2}$.

Asked in: IMO

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