$3x - 2y = 4,\ 6x + y = 13$. $y$ equals

$3x - 2y = 4,\ 6x + y = 13$. $y$ equals
  1. $1$
  2. $2$
  3. $3$
  4. $0$

Solution

Multiply 1st by $2$: $6x - 4y = 8$. Subtract from 2nd: $5y = 5 \Rightarrow y = 1$.

Asked in: MH-SSC-9

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