$2,4,8$ are in continued proportion if

$2,4,8$ are in continued proportion if
  1. $\dfrac{2}{4} = \dfrac{4}{8}$, true
  2. $\dfrac{2}{4} = \dfrac{4}{16}$
  3. $\dfrac{2}{8} = \dfrac{4}{8}$
  4. $\dfrac{2}{4} = \dfrac{8}{4}$

Solution

$\dfrac{2}{4} = \dfrac{1}{2}$ and $\dfrac{4}{8} = \dfrac{1}{2}$. Equal $\Rightarrow$ continued proportion.

Asked in: MH-SSC-9

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