$15$ tins each holding $7$ litres of oil are completely emptied into smaller tins of capacity $3$ litres…

$15$ tins each holding $7$ litres of oil are completely emptied into smaller tins of capacity $3$ litres each. How many small tins are needed?
  1. $30$
  2. $33$
  3. $35$
  4. $45$

Solution

Total oil $= 15 \times 7 = 105$ L. Small tins required $= \dfrac{105}{3} = 35$.

Asked in: IMO

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