$0.45 \mathrm{~g}$ of acid $($ molecular weight 90$)$ is neutralised by $20 \mathrm{ml}$ of $0.5 \mathrm{~N}$ caustic potash. The basicity of acid is

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Aicharya · Accepted Answer

Eq. of acid = Eq of base, $	herefore \frac{0.45}{	ext { E.wt }}=\frac{20 	imes 0.5}{1000},=$ E. $\mathrm{wt}=45$ Basicity $=\frac{	ext { M.wt }}{	ext { E.wt }}=\frac{90}{45}=2$

$0.45 \mathrm{~g}$ of acid $($ molecular weight 90$)$ is neutralised by $20 \mathrm{ml}$ of $0.5…

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