$-\dfrac{8}{12}$ in standard form is

$-\dfrac{8}{12}$ in standard form is
  1. $-\dfrac{2}{3}$
  2. $-\dfrac{4}{6}$
  3. $\dfrac{2}{3}$
  4. $-\dfrac{8}{12}$

Solution

GCD $=4$: $-\dfrac{2}{3}$.

Asked in: NSO

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