$ \begin{array}{|l|l|l|l|} \hline & \text{List-I} & & \text{List-II} \\ \hline & \text{(Molecule)} & &…

$ \begin{array}{|l|l|l|l|} \hline & \text{List-I} & & \text{List-II} \\ \hline & \text{(Molecule)} & & \text{(Shape)} \\ \hline \text { A. } & \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3} \cdot \mathrm{xH}_{2} \mathrm{O} & \text { I. } & \text { Violet } \\ \hline \text { B. } & \left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]^{4-} & \text { II. } & \text { Blood Red } \\ \hline \text { C. } & \left[\mathrm{Fe}(\mathrm{SCN})\right]^{2+} & \text { III. } & \text { Prussian Blue } \\ \hline \text { D. } & \left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} \cdot 12 \mathrm{MoO}_{3} & \text { IV. } & \text { Yellow } \\ \hline \end{array} $ Choose the correct answer from the options given below:
  1. A-III, B-I, C-II, D-IV
  2. A-I, B-II, C-III, D-IV
  3. A-IV, B-I, C-II, D-III
  4. A-II, B-III, C-IV, D-I

Solution

$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O} \rightarrow$ Prussian Blue $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-} \rightarrow$ Violet $[\mathrm{Fe}(\mathrm{SCN})]^{2+} \rightarrow$ Blood Red $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3 \rightarrow$ Yellow

Asked in: JEE Main 2024 (08 Apr Shift 1)

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