$\mathrm{Cu}^{2+}$ does not form $\mathrm{CuI}_2$. This is because $\mathrm{Cu}^{2+}$
- reduces $\mathrm{I}^{-}$to $\mathrm{I}^{3-}$
- undergoes self oxidation and reduction to form $\mathrm{Cu}$ and $\mathrm{Cu}^{3+}$
- oxidizes $\mathrm{I}^{-}$to $\mathrm{I}_2$
- is unstable in water
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 2)
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