Divide $(x^{2} - 9)$ by $(x + 3)$.

Divide $(x^{2} - 9)$ by $(x + 3)$.
  1. $x - 3$
  2. $x + 3$
  3. $x^{2} - 3$
  4. $1 - 3x$

Solution

$x^{2}-9 = (x-3)(x+3)$. Dividing by $(x+3)$ gives $x-3$.

Asked in: IMO

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