Divide $\dfrac{x^{2} - 7x + 12}{x - 4}$.

Divide $\dfrac{x^{2} - 7x + 12}{x - 4}$.
  1. $x - 3$
  2. $x + 3$
  3. $x - 4$
  4. $x + 4$

Solution

$x^{2}-7x+12 = (x-3)(x-4)$. Dividing by $(x-4)$ gives $x-3$.

Asked in: IMO

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