Divide $(6x^{3} - 9x^{2} + 12x)$ by $3x$.

Divide $(6x^{3} - 9x^{2} + 12x)$ by $3x$.
  1. $2x^{2} - 3x + 4$
  2. $2x^{2} - 3x - 4$
  3. $2x^{2} + 3x + 4$
  4. $6x^{2} - 9x + 12$

Solution

Divide each: $\dfrac{6x^{3}}{3x}=2x^{2}, \dfrac{-9x^{2}}{3x}=-3x, \dfrac{12x}{3x}=4$.

Asked in: IMO

Practice more FACTORISATION questions on Aicharya