Divide $(3x^{2} - 12)$ by $(x - 2)$.

Divide $(3x^{2} - 12)$ by $(x - 2)$.
  1. $3(x + 2)$
  2. $3(x - 2)$
  3. $3x + 12$
  4. $3x - 6$

Solution

$3x^{2}-12 = 3(x^{2}-4) = 3(x-2)(x+2)$. Dividing by $(x-2)$ gives $3(x+2)$.

Asked in: IMO

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