Divide $(2x^{2} + 7x + 3)$ by $(x + 3)$.

Divide $(2x^{2} + 7x + 3)$ by $(x + 3)$.
  1. $2x + 1$
  2. $2x - 1$
  3. $2x + 3$
  4. $x + 1$

Solution

$2x^{2}+7x+3 = (2x+1)(x+3)$. Quotient $= 2x+1$.

Asked in: IMO

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