Divide $20a^{4}b^{3}$ by $5a^{2}b$.

Divide $20a^{4}b^{3}$ by $5a^{2}b$.
  1. $4a^{2}b^{2}$
  2. $4ab^{2}$
  3. $4a^{2}b^{3}$
  4. $15a^{2}b^{2}$

Solution

$\dfrac{20a^{4}b^{3}}{5a^{2}b} = 4 \cdot a^{4-2} \cdot b^{3-1} = 4a^{2}b^{2}$.

Asked in: IMO

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