Displacement of a wave is expressed as $x(t)=5 \cos \left(628 t+\frac{\pi}{2}\right) m$. The wavelength of the wave when its velocity is $300 \mathrm{~m} / \mathrm{s}$ is :

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{x}(\mathrm{t})=5 \cos \left[628 \mathrm{t}+\frac{\pi}{2}ight] \mathrm{m} \ & 	ext { velocity }\left(\mathrm{v}_\omegaight)=300 \mathrm{~m} / \mathrm{s} \ & \mathrm{v}_{\mathrm{w}}=\frac{\omega}{\mathrm{K}} \ & 300=\frac{628}{\mathrm{~K}} \Rightarrow \mathrm{~K}=\frac{628}{300} \ & \frac{2 \pi}{\lambda}=\frac{628}{300} \Rightarrow \lambda=\frac{2 	imes 3.14 	imes 300}{628} \ & \lambda=2 \mathrm{~m}\end{aligned}$

Displacement of a wave is expressed as $x(t)=5 \cos \left(628 t+\frac{\pi}{2}\right) m$. The wavelength of…

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