Displacement $s$ of a particle at time $t$ is expressed as $s=2 t^3-9 t$. Find the acceleration at the time when the velocity vanishes.

Question

Aicharya · Accepted Answer

$s=2 t^3-9 t$
Velocity $=\frac{d s}{d t}=6 t^2-9=0 \Rightarrow t=\frac{3}{\sqrt{6}}$ Acceleration $=\frac{d^2 s}{d t^2}=\left.12 t \Rightarrow \frac{d^2 s}{d t^2}\right|_{\left(t=\frac{3}{\sqrt{6}}\right)}=6 \sqrt{6}$

Displacement $s$ of a particle at time $t$ is expressed as $s=2 t^3-9 t$. Find the acceleration at the time…

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