Dipole moment of $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}(\mathrm{I}), \mathrm{CH}_{3}…
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}(\mathrm{I}), \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(\mathrm{II})$ and $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~F}(\mathrm{III})$ is in order
- I < II < III
- I>II>III
- I < III < II
- III < I < II
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY
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