Dimensions of \(\varepsilon_{0} \mu_{0}\) are
- \(\left[L T^{-1}\right]\)
- \(\left[L T^{-2}\right]\)
- \(\left[L^{2} T^{-2}\right]\)
- \(\left[L^{-2} T^{2}\right]\)
Solution
\(C=\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}} \Rightarrow \mu_{0} \varepsilon_{0}=\frac{1}{C^{2}}=\left[L^{-2} T^{2}\right]\)
Asked in: JEE Mains - Units and Dimensions - Chapter Test