Dichromate ion is treated with base, the oxidation number of Cr in the product formed is

Dichromate ion is treated with base, the oxidation number of

Cr

in the product formed is

Solution

${Cr}_{2} O_{7}^{2 -} + {OH}^{-} ⟶ {CrO}_{4}^{2 -}$

Oxidation state of $Cr$ in ${CrO}_{4}^{2 -}$ is $+ 6$

Asked in: JEE Main 2021 (26 Feb Shift 1)

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