Diagonals $AC$ and $BD$ of parallelogram intersect at $O$. Then $AO$ equals

Diagonals $AC$ and $BD$ of parallelogram intersect at $O$. Then $AO$ equals
  1. $OC$
  2. $OB$
  3. $AC$
  4. $BD$

Solution

Diagonals bisect each other.

Asked in: MH-SSC-9

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