Diagonal of a square of side $a$ is

Diagonal of a square of side $a$ is
  1. $a\sqrt{2}$
  2. $2a$
  3. $a$
  4. $\dfrac{a}{\sqrt{2}}$

Solution

$\sqrt{a^2+a^2} = a\sqrt{2}$.

Asked in: MH-SSC-9

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