Determine the oxidation number of the underlined atom in Rb 4 Na H V 1 0 ¯ O 2 8

Determine the oxidation number of the underlined atom in Rb 4 Na H V 1 0 ¯ O 2 8
  1. +9
  2. -4 
  3. 0
  4. +5

Solution

Let the oxidation number of V be ‘a’ , then

(4 × 1) + 1 + [1 +(10 × a) + (28 × (-2))] = 0

Hence, a = +5

Asked in: JEE-TOPICTESTS-CHEMISTRY

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