Determine the oxidation number of the Mo atom in $(NH_4)_6Mo_7O_{24}$

Determine the oxidation number of the Mo atom in $(NH_4)_6Mo_7O_{24}$
  1. -5
  2. +6
  3. -3
  4. -1

Solution

Let the oxidation number of Mo be ‘a’ , then

(1 × 6) +(7 × a) + (24 × (-2)) = 0

Hence,  a = +6

Asked in: MHT CET Full Test 2

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