$T_m$ denotes the number of triangles that can be formed with the vertices of a regular polygon of $m$ sides…

$T_m$ denotes the number of triangles that can be formed with the vertices of a regular polygon of $m$ sides. If $T_{m+1}-T_m=15$, then $m$ is equal to
  1. $3$
  2. $6$
  3. $9$
  4. $12$

Solution

Given, $T_m=$ Number of triangles formed with the vertices of a polygon of $m$ sides. Also, $T_{m+1}-T_m=15$
As we know, ${ }^n C_r+{ }^n C_{r+1}={ }^{n+1} C_{r+1}$ $\therefore \quad{ }^m C_2+{ }^m C_3={ }^{m+1} C_{2+1}$ ${ }^m C_2+{ }^m C_3=15+{ }^m C_3 \quad$ [from eq. (i) $]$ $\begin{aligned} & \therefore \quad{ }^m C_2=15 \\ & \frac{m !}{2 !(m-2) !}=15 \\ & m(m-1)=30 \\ & m^2-m-30=0 \\ & (m-6)(m+5)=0 \\ & m=6-5\end{aligned}$ $\therefore m=6 \quad[\because m \neq-5]$

Asked in: AP EAMCET 2015

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