Define $f(x)=\left\{\begin{array}{cl}\frac{1-\sin x}{(\pi-2 x)^2} & ext {, if } x
eq \frac{\pi}{2} \ k & ext {, if } x=\frac{\pi}{2}\end{array} ight.$ If $f(x)$ is continuous at $x=\frac{\pi}{2}$, then $k=$

Question

Define $f(x)=\left\{\begin{array}{cl}\frac{1-\sin x}{(\pi-2 x)^2} & 	ext {, if } x 
eq \frac{\pi}{2} \ k & 	ext {, if } x=\frac{\pi}{2}\end{array}ight.$ If $f(x)$ is continuous at $x=\frac{\pi}{2}$, then $k=$

Aicharya · Accepted Answer

No solution. Refer to answer key.

Define $f(x)=\left\{\begin{array}{cl}\frac{1-\sin x}{(\pi-2 x)^2} & \text {, if } x \neq \frac{\pi}{2} \\ k…

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