Decreasing order of nucleophilicity is

Decreasing order of nucleophilicity is
  1. $\mathrm{OH}^{-}>\mathrm{NH}_2^{-}>\mathrm{CH}_3 \mathrm{O}^{-}>\mathrm{RNH}_2$
  2. $\mathrm{NH}_2^{-}>\mathrm{OH}^{-}>\mathrm{CH}_3 \mathrm{O}^{-}>\mathrm{RNH}_2$
  3. $\mathrm{NH}_2^{-}>\mathrm{CH}_3 \mathrm{O}^{-}>\mathrm{OH}^{-}>\mathrm{RNH}_2$
  4. $\mathrm{CH}_3 \mathrm{O}^{-}>\mathrm{NH}_2^{-}>\mathrm{OH}^{-}>\mathrm{RNH}_2$

Solution

If the nucleophilic atoms are in the same row of the periodic table, nucleophilicity is approximately in order of basicity. So, the order is $\mathrm{NH}_2^{-}>\mathrm{CH}_3 \mathrm{O}^{-}>\mathrm{OH}^{-}>\mathrm{RNH}_2$.

Asked in: NEET 2018

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