Decreasing order of bond angle is

Decreasing order of bond angle is
  1. $\mathrm{BeCl}_2 > \mathrm{NO}_2 > \mathrm{SO}_2$
  2. $\mathrm{BeCl}_2 > \mathrm{SO}_2 > \mathrm{NO}_2$
  3. $\mathrm{SO}_2 > \mathrm{BeCl}_2 > \mathrm{NO}_2$
  4. $\mathrm{SO}_2 > \mathrm{NO}_2 > \mathrm{BeCl}_2$

Solution

Compound: $\mathrm{BeCl}_2 > \mathrm{NO}_2 > \mathrm{SO}_2$ Angle : $180^{\circ} > 132^{\circ} > 119.5^{\circ}$

Asked in: NEET 2005

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