Current passing through a wire as function of time is given as $\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01…

Current passing through a wire as function of time is given as $\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01 \mathrm{~A}$. The charge that will flow through the wire from $t=1 s$ to $t=2 s$ is :
  1. 0.06 C
  2. 0.02 C
  3. 0.07 C
  4. 0.04 C

Solution

$\begin{aligned} & \mathrm{q}=\int \mathrm{idt} \\ & \int_0^2(0.02 \mathrm{t}+0.01) \mathrm{dt}\end{aligned}$
$\begin{aligned} & \mathrm{q}=\left[0.02 \frac{\mathrm{t}^2}{2}+0.01 \mathrm{t}\right]_1^2 \\ & =0.01(3)+0.01(1) \\ & =0.04 \mathrm{C}\end{aligned}$

Asked in: JEE Main 2025 (04 Apr Shift 1)

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