$A B$ crystallizes in a body centred cubic lattice with edge length ' $a$ ' equal to $387 \mathrm{pm}$. The…
$A B$ crystallizes in a body centred cubic lattice with edge length ' $a$ ' equal to $387 \mathrm{pm}$. The distance between two oppositively charged ions in the lattice is
$335 \mathrm{pm}$
$250 \mathrm{pm}$
$200 \mathrm{pm}$
$300 \mathrm{pm}$
Solution
For body centred cubic (bcc) lattice, distance between two oppositely charged ions,
$\begin{aligned}
\mathrm{d} & =\frac{\sqrt{3} \mathrm{a}}{2}=\frac{\sqrt{3} \times 387}{2} \mathrm{pm} \\
& =335.15 \mathrm{pm}
\end{aligned}$