Critical angle of light passing from glass to air is minimum for wavelength of
Critical angle of light passing from glass to air is minimum for wavelength of
red colour
yellow colour
green colour
blue colour
Solution
$\sin \mathrm{i}_{\mathrm{c}}=\frac{1}{\mathrm{n}}$ therefore $\mathrm{i}_{\mathrm{c}}$ will be minimum when n is maximum which in this case is for blue light.